Reuters Pattaya, Bang Lamung District, Chon Buri, Thailand
May 15, 2019, 04.15 PM
A five-year-old girl miraculously survived a 100ft fall from the eleventh floor of a hotel after sleepwalking out of her room and climbing over a ledge.
The youngster's father Decha Sookplum, 43, took his five-year-old daughter to a high school reunion party and stayed overnight at a hotel. Footage shows the girl, named only as A, walking out her room on the floor while her father was sleeping.
The door shut behind her and she was unable to get back into the room, before trying others, which were also locked. Shen then walked down the eleventh floor and made one last attempt to enter a room.
CCTV shows how the youngster then walked towards the balcony and quickly climbed across the rail to try and go down. But her slippery hands could not hold on to the rail.
She plunged more than 100ft to the hard ground below. Hotel staff rushed to the place where they heard the loud noise from the fall and found the unconscious girl. She was immediately taken to Bangkok Hospital Pattaya in an ambulance. The father, a policeman, was woken by porters who told him about the accident.
He said that he was unaware of his daughter’s behaviour and believed that she was just sleepwalking. He said: ''I didn't know when or how long she left the room until the staff told me. I think she didn’t know she left the room until she woke up and tried every way to get back to me.''
The little girl broke leg and arm and is recovering at Chonburi hospital.
A five-year-old girl miraculously survived a 100ft fall from the eleventh floor of a hotel.